Strava: Calculating the similarity of two runs
I go running several times a week and wanted to compare my runs against each other to see how similar they are.
I record my runs with the Strava app and it has an API that returns lat/long coordinates for each run in the Google encoded polyline algorithm format.
We can use the polyline library to decode these values into a list of lat/long tuples. For example:
import polyline
polyline.decode('u{~vFvyys@fS]')
[(40.63179, -8.65708), (40.62855, -8.65693)]
Once we’ve got the route defined as a set of coordinates we need to compare them. My Googling led me to an algorithm called Dynamic Time Warping
DTW is a method that calculates an optimal match between two given sequences (e.g. time series) with certain restrictions. The sequences are "warped" non-linearly in the time dimension to determine a measure of their similarity independent of certain non-linear variations in the time dimension.
The fastdtw library implements an approximation of this library and returns a value indicating the distance between sets of points.
We can see how to apply fastdtw and polyline against Strava data in the following example:
import os
import polyline
import requests
from fastdtw import fastdtw
token = os.environ["TOKEN"]
headers = {'Authorization': "Bearer {0}".format(token)}
def find_points(activity_id):
r = requests.get("https://www.strava.com/api/v3/activities/{0}".format(activity_id), headers=headers)
response = r.json()
line = response["map"]["polyline"]
return polyline.decode(line)
Now let’s try it out on two runs, 1361109741 and 1346460542:
from scipy.spatial.distance import euclidean
activity1_id = 1361109741
activity2_id = 1346460542
distance, path = fastdtw(find_points(activity1_id), find_points(activity2_id), dist=euclidean)
>>> print(distance)
2.91985018100644
These two runs are both near my house so the value is small. Let’s change the second route to be from my trip to New York:
activity1_id = 1361109741
activity2_id = 1246017379
distance, path = fastdtw(find_points(activity1_id), find_points(activity2_id), dist=euclidean)
>>> print(distance)
29383.492965394034
Much bigger!
I’m not really interested in the actual value returned but I am interested in the relative values. I’m building a little application to generate routes that I should run and I want it to come up with a routes that are different to recent ones that I’ve run. This score can now form part of the criteria.
About the author
I'm currently working on short form content at ClickHouse. I publish short 5 minute videos showing how to solve data problems on YouTube @LearnDataWithMark. I previously worked on graph analytics at Neo4j, where I also co-authored the O'Reilly Graph Algorithms Book with Amy Hodler.